The mass of carbon present in 0.5 , mol of K_ | vedclass

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Question

(D) The chemical formula $K_4[Fe(CN)_6]$ contains $6$ atoms of carbon per molecule.Therefore,$1 \, mol$ of $K_4[Fe(CN)_6]$ contains $6 \, mol$ of carb

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(D) The chemical formula $K_4[Fe(CN)_6]$ contains $6$ atoms of carbon per molecule.Therefore,$1 \, mol$ of $K_4[Fe(CN)_6]$ contains $6 \, mol$ of carbon atoms.The molar mass of carbon is $12 \, g/mol$.So,$1 \, mol$ of $K_4[Fe(CN)_6]$ contains $6 	imes 12 = 72 \, g$ of carbon.For $0.5 \, mol$ of $K_4[Fe(CN)_6]$,the mass of carbon is $0.5 	imes 72 = 36 \, g$.

The mass of carbon present in $0.5 \, mol$ of $K_4[Fe(CN)_6]$ is .............. $g$.

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