Which of the following complexes will give a | vedclass

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(C) white precipitate with $BaCl_2$ is formed due to the presence of free sulfate ions $(SO_4^{2-})$ in the solution.In the complex $[Cr(NH_3)_5Cl]SO_

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$[Cr(NH_3)_5Cl]SO_4$

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(C) white precipitate with $BaCl_2$ is formed due to the presence of free sulfate ions $(SO_4^{2-})$ in the solution.In the complex $[Cr(NH_3)_5Cl]SO_4$,the $SO_4^{2-}$ ion is present outside the coordination sphere as a counter-ion.When dissolved in water,it dissociates as follows: $[Cr(NH_3)_5Cl]SO_4 	o [Cr(NH_3)_5Cl]^{2+} + SO_4^{2-}$.The free $SO_4^{2-}$ ions react with $Ba^{2+}$ ions from $BaCl_2$ to form a white precipitate of $BaSO_4$: $Ba^{2+} + SO_4^{2-} 	o BaSO_4 \downarrow$ (white precipitate).

Which of the following complexes will give a white precipitate with $BaCl_2$ $(aq.)$?

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