The mass of benzanilide obtained from the ben | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is: $C_6H_5NH_2 + C_6H_5COCl ightarrow C_6H_5NHCOC_6H_5 + HCl$Molar mass of aniline $(C_6H_5NH_2)$ = $6 	imes 12 + 7 	imes 1 + 14

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) The reaction is: $C_6H_5NH_2 + C_6H_5COCl ightarrow C_6H_5NHCOC_6H_5 + HCl$Molar mass of aniline $(C_6H_5NH_2)$ = $6 	imes 12 + 7 	imes 1 + 14 = 93 \ g \ mol^{-1}$.Molar mass of benzanilide $(C_6H_5NHCOC_6H_5)$ = $13 	imes 12 + 11 	imes 1 + 14 + 16 = 197 \ g \ mol^{-1}$.Moles of aniline = $\frac{5.8 \ g}{93 \ g \ mol^{-1}} \approx 0.06237 \ mol$.Theoretical moles of benzanilide = $0.06237 \ mol$.Actual moles of benzanilide = $0.06237 	imes 0.82 \approx 0.05114 \ mol$.Mass of benzanilide = $0.05114 \ mol 	imes 197 \ g \ mol^{-1} \approx 10.07 \ g$.Rounding to the nearest integer,the mass is $10 \ g$.

The mass of benzanilide obtained from the benzoylation reaction of $5.8 \ g$ of aniline,if the yield of product is $82\%$,is . . . . . . $g$ (nearest integer).
(Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, N: 14, O: 16$)

Similar Questions

Which of the following isomers of $C_8H_9NO$ is the weakest base?

In the reaction $CH_3Br + KCN_{(alc)} \to X \xrightarrow[Na + C_2H_5OH]{reduction} Y$,identify $Y$.

Before nitration of amino benzene,the $-NH_2$ group is first protected by which of the following processes?

Identify $(a)$ and $(b)$ in the following reaction:
$CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (a) + (b) + 3H_2O$

In the given reaction,$[X]$ will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The mass of benzanilide obtained from the benzoylation reaction of $5.8 \ g$ of aniline,if the yield of product is $82\%$,is . . . . . . $g$ (nearest integer).(Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, N: 14, O: 16$)