In the given reaction,[X] will be: | vedclass

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Question

(D) The given reaction is the reduction of an amide,$N,N$-dimethylbenzamide $(C_6H_5CON(CH_3)_2)$,using lithium aluminum hydride $(LiAlH_4)$.$LiAlH_4$

Vedclass · Accepted Answer

$C_6H_5-CH_2-N(CH_3)_2$

Vedclass · Answer

(D) The given reaction is the reduction of an amide,$N,N$-dimethylbenzamide $(C_6H_5CON(CH_3)_2)$,using lithium aluminum hydride $(LiAlH_4)$.$LiAlH_4$ is a strong reducing agent that reduces amides to their corresponding amines.In this reaction,the carbonyl group $(C=O)$ of the amide is reduced to a methylene group $(-CH_2-)$.Therefore,the reaction is: $C_6H_5CON(CH_3)_2 + 4[H] \xrightarrow{LiAlH_4} C_6H_5CH_2N(CH_3)_2 + H_2O$.The product $[X]$ is $N,N$-dimethylbenzylamine,which corresponds to option $D$.

In the given reaction,$[X]$ will be:

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