(C) Let $x$ be the marks obtained by the student in the annual examination.The average of the three examinations is given by $\frac{62 + 48 + x}{3}$.A

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(C) Let $x$ be the marks obtained by the student in the annual examination.The average of the three examinations is given by $\frac{62 + 48 + x}{3}$.According to the problem,the average must be at least $60$,so we have the inequality:$\frac{62 + 48 + x}{3} \geq 60$Multiplying both sides by $3$,we get:$110 + x \geq 180$Subtracting $110$ from both sides,we get:$x \geq 70$Thus,the student must obtain a minimum of $70$ marks to have an average of at least $60$ marks.

Class 11 Mathematics Linear Inequalities Word problem of Linear inequalities

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The marks obtained by a student of Class $XI$ in first and second terminal examination are $62$ and $48$,respectively. Find the minimum marks he should get in the annual examination to have an average of at least $60$ marks.

A
$60$
B
$65$
C
$70$
D
$75$

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Linear Inequalities

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Word problem of Linear inequalities

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The marks obtained by a student of Class $XI$ in first and second terminal examination are $62$ and $48$,respectively. Find the minimum marks he should get in the annual examination to have an average of at least $60$ marks.

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