The major products P and Q in the following r | vedclass

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(D) Step $1$: Debromination of $2,3$-dibromo-$5$-methylhexane with $Zn$ dust leads to the formation of $5$-methylhex-$2$-ene. Step $2$: Ozonolysis $(O

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$P$$Q$$3$-methylbutanalEthanal

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(D) Step $1$: Debromination of $2,3$-dibromo-$5$-methylhexane with $Zn$ dust leads to the formation of $5$-methylhex-$2$-ene. Step $2$: Ozonolysis $(O_3)$ of $5$-methylhex-$2$-ene forms an ozonide intermediate. Step $3$: Reductive hydrolysis of the ozonide with $Zn/H_2O$ cleaves the double bond to yield two carbonyl compounds. The reaction is: $(CH_3)_2CH-CH_2-CH=CH-CH_3 + O_3 \rightarrow (CH_3)_2CH-CH_2-CHO + CH_3-CHO$. Thus,the products are $3$-methylbutanal $(P)$ and ethanal $(Q)$.

The major products $P$ and $Q$ in the following reaction sequence are:

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$HCl$ does not show the peroxide effect because the reaction mechanism involves the following steps:
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