The major products P and Q of the following r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In reaction $I$,$n$-pentyl bromide $(CH_3CH_2CH_2CH_2CH_2Br)$ reacts with $Zn/H^+$ (a reducing agent),which replaces the $Br$ atom with an $H$ ato

Vedclass · Accepted Answer

pentane; decane

Vedclass · Answer

(A) In reaction $I$,$n$-pentyl bromide $(CH_3CH_2CH_2CH_2CH_2Br)$ reacts with $Zn/H^+$ (a reducing agent),which replaces the $Br$ atom with an $H$ atom to form pentane $(CH_3CH_2CH_2CH_2CH_3)$ as product $P$.In reaction $II$,$n$-pentyl bromide reacts with $Na$ in the presence of dry ether,which is the Wurtz reaction. This reaction couples two alkyl groups to form a symmetric alkane,resulting in decane $(CH_3(CH_2)_8CH_3)$ as product $Q$.

The major products $P$ and $Q$ of the following reactions respectively are:
$I$. $n$-pentyl bromide $\xrightarrow{Zn / H^{+}} P$
$II$. $n$-pentyl bromide $\xrightarrow[\text{Dry ether}]{Na} Q$

Similar Questions

As we move from a primary alkane to a tertiary alkane (isomeric alkanes),the boiling point.......

Identify all the possible monochloro structural isomers expected to be formed on free radical monochlorination of $(CH_3)_2CHCH_2CH_3$.

Isomerism in saturated hydrocarbons is due to

When a certain alkane is mixed with chlorine and irradiated with ultraviolet light,only one monochloroalkane is formed. This alkane is likely to be:

$A$ hydrocarbon $C_{5}H_{10}$ does not react with chlorine in the dark but gives a single monochloro compound $C_{5}H_{9}Cl$ in bright sunlight. Identify the hydrocarbon.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The major products $P$ and $Q$ of the following reactions respectively are:$I$. $n$-pentyl bromide $\xrightarrow{Zn / H^{+}} P$$II$. $n$-pentyl bromide $\xrightarrow[\text{Dry ether}]{Na} Q$