Identify all the possible monochloro structur | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given molecule is $2$-methylbutane,which has the structure $(CH_3)_2CHCH_2CH_3$. There are four distinct types of hydrogen atoms in this molec

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) The given molecule is $2$-methylbutane,which has the structure $(CH_3)_2CHCH_2CH_3$. There are four distinct types of hydrogen atoms in this molecule: $1$. Primary hydrogens on the terminal methyl groups attached to the $CH$ group. $2$. The tertiary hydrogen on the $CH$ group. $3$. The secondary hydrogens on the $CH_2$ group. $4$. The primary hydrogens on the terminal methyl group attached to the $CH_2$ group. Replacing each type of hydrogen with a chlorine atom gives the following four structural isomers: $(i) (CH_3)_2CHCH_2CH_2Cl$ $(ii) (CH_3)_2CHCH(Cl)CH_3$ $(iii) (CH_3)_2C(Cl)CH_2CH_3$ $(iv) CH_3CH(CH_2Cl)CH_2CH_3$ Thus,there are $4$ possible monochloro structural isomers.

Identify all the possible monochloro structural isomers expected to be formed on free radical monochlorination of $(CH_3)_2CHCH_2CH_3$.

Similar Questions

Which of the following does not react with $PCl_5$?

Select the reaction$(s)$ that would result in the formation of $2-$bromopropane.
$(I) \ CH_3-CH=CH_2 + HBr \xrightarrow{\text{peroxide}}$
$(II) \ CH_3-CH=CH_2 + HBr \xrightarrow{CCl_4}$
$(III) \ CH_3-CH_2-CH_3 + Br_2 \xrightarrow{hv}$
$(IV) \ CH_3-CH=CH_2 + Br_2 \xrightarrow{CCl_4}$

Which of the following shows only one monobrominated compound upon reaction with $Br_2$ in the presence of light?

Explain the difference in the boiling points of the branched structures of pentane $(C_5H_{12})$. Explain how branching affects the boiling point of isomeric alkanes.

The $4^{th}$ higher homologue of ethane is

Vedclass Test Series

Exam Paper Generator

Online Exam Module