The major product of the reaction is:

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(A) The reaction involves the acid-catalyzed hydration of $1$-methylcyclopentene.In the presence of an acid catalyst $(H^+)$,water adds across the dou

Vedclass · Accepted Answer

$I$

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(A) The reaction involves the acid-catalyzed hydration of $1$-methylcyclopentene.In the presence of an acid catalyst $(H^+)$,water adds across the double bond of the alkene.This reaction proceeds via an electrophilic addition mechanism,where the proton $(H^+)$ first adds to the less substituted carbon of the double bond to form the more stable carbocation intermediate.For $1$-methylcyclopentene,the proton adds to the $CH$ group,resulting in a tertiary carbocation at the carbon atom already bearing the methyl group.Subsequently,a water molecule attacks this tertiary carbocation,followed by deprotonation to yield $1$-methylcyclopentan-$1$-ol.This follows the Markownikoff rule,which states that the nucleophile $(-OH)$ attaches to the more substituted carbon atom.Therefore,the major product is structure $I$.

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