What is the product formed when propene react | vedclass

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(B) The reaction of propene $(CH_3-CH=CH_2)$ with $HCl$ follows the Markovnikov addition rule. Peroxide effect (Kharasch effect) is only applicable to

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$2$-chloropropane

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(B) The reaction of propene $(CH_3-CH=CH_2)$ with $HCl$ follows the Markovnikov addition rule. Peroxide effect (Kharasch effect) is only applicable to $HBr$ and not to $HCl$ or $HI$. Therefore,the addition of $HCl$ to propene in the presence of peroxide still follows the Markovnikov rule,where the $Cl^-$ ion attaches to the more substituted carbon atom. Thus,the major product is $2$-chloropropane $(CH_3-CHCl-CH_3)$.

What is the product formed when propene reacts with $HCl$ in the presence of peroxide?

Similar Questions

The general formula of alkenes is:

Consider the following reactions:
$Ph-CH_2-CH=CH_2 \xrightarrow{H^+/H_2O} P$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) NaBD_4]{(i) Hg(OAc)_2, H_2O} Q$
$Ph-CH_2-CH=CH_2 \xrightarrow[(ii) H_2O_2/OH^-]{(i) BD_3, THF} R$
Identify the products $P, Q$ and $R$.

$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{DBr} \text{Product (Major)}$. The product will be:

Predict the product of the following reaction: $CH_3-CH=CH_2 \xrightarrow[(2) NaBD_4]{(1) H_2O, Hg(OCOCH_3)_2} \text{Product}$

Which of the following reactions proceeds via a secondary free radical?

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