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(C) The reaction involves a nucleophilic substitution with $NaN_3$ (azide ion,$N_3^-$) acting as the nucleophile.$Br^-$ is a better leaving group than

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(C) The reaction involves a nucleophilic substitution with $NaN_3$ (azide ion,$N_3^-$) acting as the nucleophile.$Br^-$ is a better leaving group than $Cl^-$,so the substitution occurs at the carbon atom attached to the bromine atom.Since $NaN_3$ is a strong nucleophile and the reaction proceeds via an $S_N2$ mechanism,the nucleophile attacks from the side opposite to the leaving group,resulting in an inversion of configuration at the chiral center.Therefore,the $-N_3$ group replaces the $-Br$ group with inversion of configuration.

What is the principal product of the following reaction?
$CH_3-CH(Br)-CH_2-CH_2-CH(Cl)-CH_3 + NaN_3 \rightarrow \text{Product}$

Similar Questions

Which of the following statements is correct for the reactivity in $S_N2$ reaction?

Which compound might be synthesized by the $S_N2$ displacement of an alkyl-halide?

The reactivity of $2-$bromo$-2-$methylbutane $(I)$,$1-$bromopentane $(II)$ and $2-$bromopentane $(III)$ towards $S_N2$ displacement is such that :

The correct description of the product in the following reaction is:
$CH_3-CH(Br)-CH_2OCH_3 \text{ } ((R)) \xrightarrow{NaCN, \text{acetone}} CH_3-CH(CN)-CH_2OCH_3$

Arrange the following three chlorides in decreasing order of their reactivity towards $S_{N^1}$ reaction.

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What is the principal product of the following reaction?$CH_3-CH(Br)-CH_2-CH_2-CH(Cl)-CH_3 + NaN_3 \rightarrow \text{Product}$