The major product of the following reaction is:
$Ph-CH(CH_3)-CH(Br)-CH_2-CH_2-Br \xrightarrow{KOH \text{ (alc, excess)}, \Delta} ?$

Match the following:

Reactants	Products
$A$. $C_2H_5Cl$,moist $Ag_2O$	$I$. $CH_3CH_2ONO$
$B$. $C_2H_5Cl$,aqueous ethanolic $AgCN$	$II$. $C_2H_4$
$C$. $C_2H_5Cl$,aqueous ethanolic $AgNO_2$	$III$. $CH_3CH_2OH$
$D$. $C_2H_5Cl$,ethanolic $KOH$	$IV$. $CH_3CH_2NC$

The correct match is:

The following reaction is supposed to take place through the $S_N1$ mechanism: $CH_3-C(Ph)(OH)-CH_2-CH_3 \xrightarrow{HI} \text{products}$. If the configuration of the substrate is $D$,then the configuration of the products will be:

The correct decreasing order of $SN^2$ reactivity of the following alkyl halides is:
$(I)$ $CH_2=CH-Br$
$(II)$ $CH_3-Br$
$(III)$ $CH_3-CH(Br)-CH_3$
$(IV)$ $CH_3-CH_2-Br$

The correct reactivity order for $S_N2$ reaction is:
$(i)$ $CH_3COCH_2Cl$
(ii) $CH_2=CH-CH_2Cl$
(iii) $CH_3CH_2CH_2Cl$

Which of the following halides will give $S_N 1$ reaction fastest?