The following reaction is supposed to take place through the $S_N1$ mechanism: $CH_3-C(Ph)(OH)-CH_2-CH_3 \xrightarrow{HI} \text{products}$. If the configuration of the substrate is $D$,then the configuration of the products will be:
- A$D$
- B$L$
- C$50\% D$ and $50\% L$
- DMay be $D$ or $L$
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