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Question

(A) The reaction proceeds as follows:$1$. Hydroboration-oxidation of methylenecyclopentane with $(i) B_2H_6$ and $(ii) H_2O_2/NaOH$ yields cyclopentyl

Vedclass · Accepted Answer

Cyclopentylphenylmethanol

Vedclass · Answer

(A) The reaction proceeds as follows:$1$. Hydroboration-oxidation of methylenecyclopentane with $(i) B_2H_6$ and $(ii) H_2O_2/NaOH$ yields cyclopentylmethanol.$2$. Oxidation of the primary alcohol with $PCC$ (Pyridinium chlorochromate) yields cyclopentanecarbaldehyde.$3$. Nucleophilic addition of the Grignard reagent $PhMgBr$ to the aldehyde,followed by hydrolysis with $(v) H_2O$,yields the secondary alcohol,cyclopentylphenylmethanol.

The major product of the following reaction is:

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