A mixture of benzaldehyde and formaldehyde on | vedclass

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Question

(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$ in the presence of aqueous $NaOH$ is a $Crossed \ Cannizzaro \ reaction$

Vedclass · Accepted Answer

Benzyl alcohol and sodium formate

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(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$ in the presence of aqueous $NaOH$ is a $Crossed \ Cannizzaro \ reaction$.In this reaction,the more reactive aldehyde (formaldehyde) undergoes oxidation to form a formate salt,while the less reactive aldehyde (benzaldehyde) undergoes reduction to form an alcohol.$C_6H_5CHO + HCHO \xrightarrow{NaOH_{(aq)}} C_6H_5CH_2OH + HCOONa$Thus,the products are benzyl alcohol $(C_6H_5CH_2OH)$ and sodium formate $(HCOONa)$.

$A$ mixture of benzaldehyde and formaldehyde on heating with aqueous $NaOH$ solution gives:

Similar Questions

The product $(A)$ in the following reaction is:

$CaOCl_2 + H_2O \longrightarrow Ca(OH)_2 + X$
$X + CH_3CHO \longrightarrow Y$
$Y + Ca(OH)_2 \longrightarrow CHCl_3$
What is '$Y$'?

The product $(B)$ in the above reaction is:

Product $(C)$ is

The Clemmensen reduction is represented by:

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