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(C) The reaction proceeds as follows:$1$. Reaction with alcoholic $NH_3$ converts the acid chloride $(R-COCl)$ into an amide $(R-CONH_2)$: $CH_3-CH(CH

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$CH_3-CH(CH_3)-CH_2-CH_2OH$

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(C) The reaction proceeds as follows:$1$. Reaction with alcoholic $NH_3$ converts the acid chloride $(R-COCl)$ into an amide $(R-CONH_2)$: $CH_3-CH(CH_3)-CH_2-CH_2-COCl \xrightarrow{NH_3} CH_3-CH(CH_3)-CH_2-CH_2-CONH_2$.$2$. The Hofmann bromamide degradation reaction $(NaOH, Br_2)$ converts the amide into a primary amine $(R-NH_2)$: $CH_3-CH(CH_3)-CH_2-CH_2-CONH_2 \xrightarrow{NaOH, Br_2} CH_3-CH(CH_3)-CH_2-CH_2-NH_2$.$3$. Treatment with $NaNO_2/HCl$ at low temperature converts the primary aliphatic amine into a diazonium salt,which is unstable and decomposes in the presence of water $(H_2O)$ to form an alcohol: $CH_3-CH(CH_3)-CH_2-CH_2-NH_2$ $\xrightarrow{NaNO_2, HCl} [CH_3-CH(CH_3)-CH_2-CH_2-N_2^+Cl^-]$ $\xrightarrow{H_2O} CH_3-CH(CH_3)-CH_2-CH_2-OH$.Thus,the major product is $CH_3-CH(CH_3)-CH_2-CH_2OH$.

The major product of the following reaction is:

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