The major product in Reimer-Tiemann reaction | vedclass

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Question

(A) The Reimer-Tiemann reaction involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous base like sodium hydroxide $

Vedclass · Accepted Answer

Salicylaldehyde,$CHCl_3$,$Aq. NaOH$

Vedclass · Answer

(A) The Reimer-Tiemann reaction involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous base like sodium hydroxide $(NaOH)$.This reaction results in the introduction of a formyl group $(-CHO)$ at the ortho position of the phenol ring,yielding salicylaldehyde (o-hydroxybenzaldehyde) as the major product.Therefore,$X$ is salicylaldehyde,$Y$ is $CHCl_3$,and $Z$ is $Aq. NaOH$.

The major product in Reimer-Tiemann reaction is $X$. The reactants are $Y$ and $Z$. $X$,$Y$ and $Z$ are respectively.

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