The major product P formed in the following s | vedclass

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(D) The reaction sequence is as follows:$1$. Treatment of the carboxylic acid with $SOCl_2$ converts it into an acid chloride: $Ph-CH=CH-CH_2-COOH \xr

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(D) The reaction sequence is as follows:$1$. Treatment of the carboxylic acid with $SOCl_2$ converts it into an acid chloride: $Ph-CH=CH-CH_2-COOH \xrightarrow{SOCl_2} Ph-CH=CH-CH_2-COCl$.$2$. Reaction with $R-NH_2$ (amine) converts the acid chloride into an amide: $Ph-CH=CH-CH_2-COCl \xrightarrow{R-NH_2} Ph-CH=CH-CH_2-CONHR$.$3$. Reduction with $LiAlH_4$ followed by $H_3O^+$ reduces the amide group $(-CONHR)$ to an amine group $(-CH_2NHR)$: $Ph-CH=CH-CH_2-CONHR \xrightarrow{LiAlH_4, H_3O^+} Ph-CH=CH-CH_2-CH_2NHR$.Thus,the final product is $Ph-CH=CH-CH_2-CH_2NHR$.

The major product $P$ formed in the following sequence of reactions is

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