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(B) The reaction involves the acid-catalyzed dehydration of an alcohol using concentrated $H_2SO_4$.$1.$ Protonation of the $-OH$ group followed by th

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(B) The reaction involves the acid-catalyzed dehydration of an alcohol using concentrated $H_2SO_4$.$1.$ Protonation of the $-OH$ group followed by the loss of $H_2O$ forms a secondary carbocation: $C_6H_5-CH_2-CH^+-CH(CH_3)_2$.$2.$ $A$ $1,2-H$ shift occurs from the tertiary carbon to form a more stable tertiary carbocation: $C_6H_5-CH_2-C^+(CH_3)_2$.$3.$ Elimination of a proton from the benzylic carbon results in the formation of the most stable alkene,which is trisubstituted and conjugated with the benzene ring: $C_6H_5-CH=C(CH_3)_2$. This corresponds to the structure in option $B$.

The main product of the following reaction is:
$C_6H_5-CH_2-CH(OH)-CH(CH_3)_2 \xrightarrow{conc. H_2SO_4} ?$

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The main product of the following reaction is:$C_6H_5-CH_2-CH(OH)-CH(CH_3)_2 \xrightarrow{conc. H_2SO_4} ?$