Which of the following substances is the most | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The acidity of alcohols is determined by the stability of the conjugate base (alkoxide ion). Electron-withdrawing groups ($-I$ effect) stabilize t

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-CHF-OH$

Vedclass · Answer

(D) The acidity of alcohols is determined by the stability of the conjugate base (alkoxide ion). Electron-withdrawing groups ($-I$ effect) stabilize the negative charge on the oxygen atom,thereby increasing acidity. The strength of the $-I$ effect depends on the electronegativity of the substituent and its distance from the $-OH$ group. Fluorine $(F)$ has a stronger $-I$ effect than Iodine $(I)$. In option $(D)$,the fluorine atom is on the carbon directly attached to the $-OH$ group (alpha-carbon),which provides the strongest $-I$ effect due to the shortest distance. Therefore,$CH_3-CH_2-CH_2-CHF-OH$ is the most acidic.

Which of the following substances is the most acidic due to the hydroxyl proton?

Similar Questions

$CH_3-CH(CH_3)-CH(OH)-CH_3$ $\xrightarrow[350^\circ C]{Al_2O_3} (A)$ $\xrightarrow[(ii) AgOH]{(i) HI} (B)$
Product $(B)$ of the above reaction is:

In the Victor-Meyer's test,the colours given by $1^o$,$2^o$,and $3^o$ alcohols are respectively:

$2,3-$epoxybutane is the anhydride of

$PhMgBr + (CH_3)_2CH-OH \to A$. Identify the product $A$.

Absolute alcohol is converted into diethyl ether by heating at $410 \, K$ in the presence of which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module