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(B) The reaction shown is the Balz-Schiemann reaction. $1$. Benzenediazonium chloride reacts with fluoroboric acid $(HBF_4)$ to form benzenediazonium

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Fluorobenzene

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(B) The reaction shown is the Balz-Schiemann reaction. $1$. Benzenediazonium chloride reacts with fluoroboric acid $(HBF_4)$ to form benzenediazonium fluoroborate $(C_6H_5N_2^ BF_4^-)$,which precipitates as a solid salt. $2$. Upon heating $(\Delta)$,this salt undergoes thermal decomposition to release nitrogen gas $(N_2)$ and boron trifluoride $(BF_3)$,resulting in the formation of fluorobenzene $(C_6H_5F)$.

The main product of the following reaction will be:

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