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Question

(B) The relationship between absolute permeability $\mu$,relative permeability $\mu_r$,and magnetic susceptibility $\chi$ is given by: $\mu = \mu_r \m

Vedclass · Accepted Answer

$2.4 \pi 	imes 10^{-4}$

Vedclass · Answer

(B) The relationship between absolute permeability $\mu$,relative permeability $\mu_r$,and magnetic susceptibility $\chi$ is given by: $\mu = \mu_r \mu_0 = (1 + \chi) \mu_0$ Given: $\chi = 599$ $\mu_0 = 4 \pi 	imes 10^{-7} 	ext{ T m/A}$ Substituting the values: $\mu = (1 + 599) 	imes (4 \pi 	imes 10^{-7}) 	ext{ T m/A}$ $\mu = 600 	imes 4 \pi 	imes 10^{-7} 	ext{ T m/A}$ $\mu = 2400 \pi 	imes 10^{-7} 	ext{ T m/A}$ $\mu = 2.4 \pi 	imes 10^{-4} 	ext{ T m/A}$ Thus,the absolute permeability is $2.4 \pi 	imes 10^{-4} 	ext{ T m/A}$.

The magnetic susceptibility of the material of a rod is $599$. The absolute permeability of the material of the rod will be $\left[\mu_0=4 \pi \times 10^{-7} \text{ SI unit}\right]$.

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