$A$ domain in a ferromagnetic substance is in the form of a cube of side $1 \mu m$. If it contains $8 \times 10^{10}$ atoms and each atomic dipole has a dipole moment of $9 \times 10^{-24} \ A \cdot m^{2}$,then the magnetisation of the domain is
- A$7.2 \times 10^{9} \ A/m$
- B$7.2 \times 10^{5} \ A/m$
- C$7.2 \times 10^{12} \ A/m$
- D$7.2 \times 10^{3} \ A/m$
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The magnetic moment of a sample of $2 \text{ g}$ is $8 \times 10^{-7} \text{ Am}^2$. If its density is $4 \text{ g/cm}^3$,then the magnetization of the sample in $\text{Am}^{-1}$ is:
Explain the magnetic susceptibility $(\chi)$ of a material. From it,explain the relative magnetic permeability and magnetic permeability of the material. Obtain the relation between them.
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View SolutionThe dipole moment of each molecule of a paramagnetic gas is $1.5 \times 10^{-23} \, A \cdot m^2$. The temperature of the gas is $27 \, ^\circ C$ and the number of molecules per unit volume is $2 \times 10^{26} \, m^{-3}$. The maximum possible intensity of magnetization in the gas will be:
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View SolutionThe magnetic susceptibility of a ferromagnetic substance is
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View Solution$A$ material of $0.25 \ cm^2$ cross-sectional area is placed in a magnetic field of strength $(H) 1000 \ Am^{-1}$. Then,the magnetic flux produced is (Susceptibility of material is $313$) (Permeability of free space,$\mu_0 = 4 \pi \times 10^{-7} \ Hm^{-1}$)
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