The magnetic potential energy stored in a cer | vedclass

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Question

(C) The magnetic potential energy $U$ stored in an inductor of inductance $L$ carrying current $I$ is given by the formula:$U = \frac{1}{2} L I^{2}$Gi

Vedclass · Accepted Answer

$13.89$

Vedclass · Answer

(C) The magnetic potential energy $U$ stored in an inductor of inductance $L$ carrying current $I$ is given by the formula:$U = \frac{1}{2} L I^{2}$Given:$U = 25\, mJ = 25 	imes 10^{-3}\, J$$I = 60\, mA = 60 	imes 10^{-3}\, A = 6 	imes 10^{-2}\, A$Substituting the values into the formula:$25 	imes 10^{-3} = \frac{1}{2} 	imes L 	imes (6 	imes 10^{-2})^{2}$$25 	imes 10^{-3} = \frac{1}{2} 	imes L 	imes 36 	imes 10^{-4}$$25 	imes 10^{-3} = L 	imes 18 	imes 10^{-4}$$L = \frac{25 	imes 10^{-3}}{18 	imes 10^{-4}}$$L = \frac{250}{18} = 13.888...\, H \approx 13.89\, H$.

The magnetic potential energy stored in a certain inductor is $25\, mJ,$ when the current in the inductor is $60\, mA.$ This inductor is of inductance ......$H$.

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