The magnetic moment of a transition metal com | vedclass

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Question

$Cr ^{+2}:[ Ar ], 3 d ^4, 4 s ^0 n =4, \mu=\sqrt{4(4+2)}=\sqrt{24}$

$=4.89\,BM$

$Mn ^{+2}:[ Ar ], 3 d ^5, 4 s ^0 n =5, \mu=\sqrt{5(5+2)}=\sqrt{3

Vedclass · Accepted Answer

$V ^{2+}$

Vedclass · Answer

$Cr ^{+2}:[ Ar ], 3 d ^4, 4 s ^0 n =4, \mu=\sqrt{4(4+2)}=\sqrt{24}$

$=4.89\,BM$

$Mn ^{+2}:[ Ar ], 3 d ^5, 4 s ^0 n =5, \mu=\sqrt{5(5+2)}=\sqrt{35}$

$=5.91\,BM$

$V ^{+2}:[ Ar ], 3 d ^3, 4 s ^0 n =3, \mu=\sqrt{3(3+2)}=\sqrt{15}$

$=3.87\,BM$

$Ti ^{+2}:[ Ar ], 3 d ^2, 4 s ^0 n =2, \mu=\sqrt{2(2+2)}=\sqrt{8}$

$=2.82\,BM$

The magnetic moment of a transition metal compound has been calculated to be $3.87$ $B.M.$ The metal ion is

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