Which of the following ions has the least mag | vedclass

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Question

(a) $C{u^{ + 2}}$$\mu = \sqrt {n(n + 2)} $ (magnetic moment)

$\mu \propto \sqrt n $

$C{u^{ + 2}}$ there is only $ 1$  unpaired electron so

Vedclass · Accepted Answer

$C{u^{ + 2}}$

Vedclass · Answer

(a) $C{u^{ + 2}}$$\mu = \sqrt {n(n + 2)} $ (magnetic moment)

$\mu \propto \sqrt n $

$C{u^{ + 2}}$ there is only $ 1$  unpaired electron so its magnetic moment is least.


	
		
			
			S.No
			
			
			Ion
			
			
			Electronic configuration
			
			
			No. of unpaired electrons
			
		
		
			
			$(i)$
			
			
			$C{u^{ + 2}}$
			
			
			${d^9}$
			
			
			$1$
			
		
		
			
			$(ii)$
			
			
			$N{i^{ + 2}}$
			
			
			${d^8}$
			
			
			$2$
			
		
		
			
			$(iii)$
			
			
			$C{o^{ + 2}}$
			
			
			${d^7}$
			
			
			$3$
			
		
		
			
			$(iv)$
			
			
			$F{e^{ + 2}}$
			
			
			${d^6}$
			
			
			$4$

Which of the following ions has the least magnetic moment

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