The magnetic flux through a circuit of resist | vedclass

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(B) According to Faraday's law of electromagnetic induction,the induced electromotive force $(EMF)$ is given by $\varepsilon = \frac{\Delta \phi}{\Del

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$\frac{\Delta \phi}{R}$

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(B) According to Faraday's law of electromagnetic induction,the induced electromotive force $(EMF)$ is given by $\varepsilon = \frac{\Delta \phi}{\Delta t}$.Since the circuit has resistance $R$,the induced current $I$ is given by $I = \frac{\varepsilon}{R} = \frac{\Delta \phi}{R \Delta t}$.The total charge $Q$ that passes through the circuit is the product of current and time: $Q = I 	imes \Delta t$.Substituting the expression for $I$,we get $Q = \left( \frac{\Delta \phi}{R \Delta t} ight) 	imes \Delta t$.Therefore,the total quantity of electric charge is $Q = \frac{\Delta \phi}{R}$.

The magnetic flux through a circuit of resistance $R$ changes by an amount $\Delta \phi$ in the time $\Delta t$. The total quantity of electric charge $Q$ which passes during this time through any point of the circuit is

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