The magnetic flux linked to a circular coil of radius $R$ is given by $\phi = 2t^3 + 4t^2 + 2t + 5 \; Wb$. The magnitude of the induced $emf$ in the coil at $t = 5 \; s$ is $.......... \; V$.

In the diagram shown,if a bar magnet is moved along the common axis of two single-turn coils $A$ and $B$ in the direction of the arrow,what happens to the induced current?

The coil and magnet are moved in the same direction with the same speed $V$. The induced e.m.f. is

Two identical metallic square loops $L_1$ and $L_2$ are placed next to each other with their sides parallel on a smooth horizontal table. Loop $L_1$ is fixed and a current which increases as a function of time is passed through it. Then,loop $L_2$ is

$A$ closed planar wire loop of area $A$ and arbitrary shape is placed in a uniform magnetic field of magnitude $B$,with its plane perpendicular to the magnetic field. The resistance of the wire loop is $R$. The loop is now turned upside down by $180^o$ so that its plane again becomes perpendicular to the magnetic field. The total charge that must have flowed through the wire ring in the process is

$A$ coil of surface area $200 \ cm^2$ having $25$ turns is held perpendicular to the magnetic field of intensity $0.02 \ Wb/m^2$. The resistance of the coil is $1 \ \Omega$. If it is removed from the magnetic field in $1 \ s$,the induced charge in the coil is . . . . . . $C$.