In the diagram shown,if a bar magnet is moved | vedclass

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(D) According to Lenz's Law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.As the bar magne

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Induced currents in $A$ and $B$ are in opposite directions.

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(D) According to Lenz's Law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.As the bar magnet moves towards coil $B$,the magnetic flux through $B$ increases. To oppose this,coil $B$ will develop a magnetic pole facing the $S$-pole of the magnet,which acts as an $S$-pole. This corresponds to a clockwise current when viewed from the right.Simultaneously,the bar magnet moves away from coil $A$. The magnetic flux through $A$ decreases. To oppose this,coil $A$ will develop a magnetic pole facing the $N$-pole of the magnet,which acts as an $S$-pole. This corresponds to a counter-clockwise current when viewed from the left.Since the coils are on opposite sides of the magnet,the currents induced in $A$ and $B$ will be in opposite directions relative to the axis.

In the diagram shown,if a bar magnet is moved along the common axis of two single-turn coils $A$ and $B$ in the direction of the arrow,what happens to the induced current?

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