The magnetic field of an electromagnetic wave is given by $\vec B = 1.6 \times 10^{-6} \cos(2 \times 10^7 z + 6 \times 10^{15} t) (2\hat i + \hat j) \text{ Wb/m}^2$. The associated electric field will be

  • A
    $\vec E = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (-\hat i + 2\hat j) \text{ V/m}$
  • B
    $\vec E = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (-2\hat j + 2\hat i) \text{ V/m}$
  • C
    $\vec E = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (\hat i + 2\hat j) \text{ V/m}$
  • D
    $\vec E = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (2\hat i + \hat j) \text{ V/m}$

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