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Question

(C) The minimum frequency required for photoelectric emission is called the threshold frequency $(
u_0)$.It is related to the work function $(W_0)$ b

Vedclass · Accepted Answer

$4 	imes 10^{14} \ Hz$

Vedclass · Answer

(C) The minimum frequency required for photoelectric emission is called the threshold frequency $(
u_0)$.It is related to the work function $(W_0)$ by the equation: $W_0 = h
u_0$.Given: $W_0 = 1.65 \ eV = 1.65 	imes 1.6 	imes 10^{-19} \ J$ and Planck's constant $h = 6.6 	imes 10^{-34} \ J \cdot s$.Substituting these values into the equation:$
u_0 = \frac{W_0}{h} = \frac{1.65 	imes 1.6 	imes 10^{-19}}{6.6 	imes 10^{-34}}$$
u_0 = \frac{2.64 	imes 10^{-19}}{6.6 	imes 10^{-34}} = 0.4 	imes 10^{15} \ Hz = 4 	imes 10^{14} \ Hz$.Therefore,the correct option is $C$.

The lowest frequency of light that will cause the emission of photoelectrons from the surface of a metal (for which work function is $1.65 \ eV$) will be

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