The logically equivalent proposition of $p \Leftrightarrow q$ is
- A$(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$
- B$p \wedge q$
- C$(p \wedge q) \vee (q \Rightarrow p)$
- D$(p \wedge q) \Rightarrow (q \vee p)$
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Similar Questions
The logically equivalent statement of $(\sim p \wedge q) \vee (\sim p \wedge \sim q) \vee (p \wedge \sim q)$ is
If $(\sim p \wedge q) \rightarrow r$ is false,then the truth values of $p, q, r$ are respectively:
The statement $(p \wedge (\sim q)) \vee ((\sim p) \wedge q) \vee ((\sim p) \wedge (\sim q))$ is equivalent to
DifficultJEE MAIN 2023
View SolutionStatement-$I$: $(p \wedge \sim q) \wedge (\sim p \wedge q)$ is a contradiction.
Statement-$II$: $(p$ $\rightarrow q) \Leftrightarrow (\sim q$ $\rightarrow \sim p)$ is a tautology.
Statement-$II$: $(p$ $\rightarrow q) \Leftrightarrow (\sim q$ $\rightarrow \sim p)$ is a tautology.
Difficult
View SolutionIf the statement $p \vee \sim(q \wedge r)$ is false,then the truth values of $p, q$ and $r$ are respectively:
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