The logic circuit in the figure is equivalent | vedclass

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(D) Let the inputs be $A$ and $B$. The first gate is a $NAND$ gate,so its output is $Y_1 = \overline{A \cdot B}$.This output $Y_1$ is fed into both in

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$NAND$ gate

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(D) Let the inputs be $A$ and $B$. The first gate is a $NAND$ gate,so its output is $Y_1 = \overline{A \cdot B}$.This output $Y_1$ is fed into both inputs of a $NOR$ gate. The output of a $NOR$ gate with inputs $Y_1$ and $Y_1$ is $Y_2 = \overline{Y_1 + Y_1} = \overline{Y_1}$.Substituting $Y_1$,we get $Y_2 = \overline{\overline{A \cdot B}} = A \cdot B$.This output $Y_2$ is then passed through a $NOT$ gate. The final output is $Y = \overline{Y_2} = \overline{A \cdot B}$.Since the final output is $\overline{A \cdot B}$,the given logic circuit is equivalent to a $NAND$ gate.

$A$	$B$	$C$	$Y$
$0$	$0$	$0$	$1$
$0$	$0$	$1$	$1$
$0$	$1$	$0$	$0$
$0$	$1$	$1$	$0$
$1$	$0$	$0$	$1$
$1$	$0$	$1$	$1$
$1$	$1$	$0$	$0$
$1$	$1$	$1$	$0$

The logic circuit in the figure is equivalent to

Similar Questions

The $XOR$ gate gives an output of $1$ only when the two inputs are . . . . .

For the given truth table,where $A, B$,and $C$ are inputs and $Y$ is the output,determine the functional form of the circuit.
$A$ $B$ $C$ $Y$
$0$ $0$ $0$ $1$
$0$ $0$ $1$ $1$
$0$ $1$ $0$ $0$
$0$ $1$ $1$ $0$
$1$ $0$ $0$ $1$
$1$ $0$ $1$ $1$
$1$ $1$ $0$ $0$
$1$ $1$ $1$ $0$

For which of the following Boolean expressions is the result always zero?

Write the truth table for the circuit shown in the figure. Name the gate that the circuit resembles.

In the Boolean algebra,$(\overline {\bar A \cdot \bar B} ) \cdot A$ is equal to:

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$A$	$B$	$C$	$Y$
$0$	$0$	$0$	$1$
$0$	$0$	$1$	$1$
$0$	$1$	$0$	$0$
$0$	$1$	$1$	$0$
$1$	$0$	$0$	$1$
$1$	$0$	$1$	$1$
$1$	$1$	$0$	$0$
$1$	$1$	$1$	$0$

$A$	$B$	$C$	$Y$
$0$	$0$	$0$	$1$
$0$	$0$	$1$	$1$
$0$	$1$	$0$	$0$
$0$	$1$	$1$	$0$
$1$	$0$	$0$	$1$
$1$	$0$	$1$	$1$
$1$	$1$	$0$	$0$
$1$	$1$	$1$	$0$