The limiting molar conductivities of the give | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The limiting molar conductivities of the given electrolytes are calculated using Kohlrausch's law: $\lambda^{\circ}_{KCl} = \lambda^{\circ}_{K^{+}

Vedclass · Accepted Answer

$KCl < CaCl_{2} < K_{2}SO_{4}$

Vedclass · Answer

(A) The limiting molar conductivities of the given electrolytes are calculated using Kohlrausch's law: $\lambda^{\circ}_{KCl} = \lambda^{\circ}_{K^{+}} + \lambda^{\circ}_{Cl^{-}} = 73.5 + 76.3 = 149.8 \ S \ cm^{2} \ mol^{-1}$ $\lambda^{\circ}_{CaCl_{2}} = \lambda^{\circ}_{Ca^{2+}} + 2\lambda^{\circ}_{Cl^{-}} = 119.0 + 2 	imes 76.3 = 271.6 \ S \ cm^{2} \ mol^{-1}$ $\lambda^{\circ}_{K_{2}SO_{4}} = 2\lambda^{\circ}_{K^{+}} + \lambda^{\circ}_{SO_{4}^{2-}} = 2 	imes 73.5 + 160.0 = 307.0 \ S \ cm^{2} \ mol^{-1}$ Comparing the values,the order is: $\lambda^{\circ}_{KCl} < \lambda^{\circ}_{CaCl_{2}} < \lambda^{\circ}_{K_{2}SO_{4}}$.

The limiting molar conductivities of the given electrolytes at $298 \ K$ follow the order: $\lambda^{\circ}_{(K^{+})} = 73.5, \lambda^{\circ}_{(Cl^{-})} = 76.3, \lambda^{\circ}_{(Ca^{2+})} = 119.0, \lambda^{\circ}_{(SO_{4}^{2-})} = 160.0 \ S \ cm^{2} \ mol^{-1}$.

Similar Questions

The molar conductivity is maximum for the solution of concentration $...........$ $M$.

Resistance of a conductivity cell at $298 \ K$ for $0.0100 \ M \ KCl$ is $161.8 \ \Omega$. Resistance becomes $190 \ \Omega$ when $0.005 \ M \ NaOH$ solution is filled in this cell. Calculate: $(i)$ cell constant,$(ii)$ specific conductivity for $NaOH$ solution,and $(iii)$ molar conductivity.

At a particular temperature,the ratio of equivalent conductance to specific conductance of a $0.01 \ N$ $NaCl$ solution is

The variation of molar conductivity with concentration of an electrolyte $X$ in aqueous solution is shown in the given figure.
The electrolyte $X$ is :

Which solution of $NaNO_3$ will have maximum specific conductance in $N$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module