The lengths of $62$ leaves of a plant are measured in millimetres and the data is represented in the following table:
Length (in mm) Number of leaves
$118-126$ $8$
$127-135$ $10$
$136-144$ $12$
$145-153$ $17$
$154-162$ $7$
$163-171$ $5$
$172-180$ $3$

Draw a histogram to represent the data above.

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(N/A) The given table is in inclusive form. To draw a histogram,we must first convert it into an exclusive form by finding the difference between the upper limit of one class and the lower limit of the next class. Here,the difference is $127 - 126 = 1$. We subtract $0.5$ from each lower limit and add $0.5$ to each upper limit.
Length (in mm) Number of leaves
$117.5-126.5$ $8$
$126.5-135.5$ $10$
$135.5-144.5$ $12$
$144.5-153.5$ $17$
$153.5-162.5$ $7$
$162.5-171.5$ $5$
$171.5-180.5$ $3$

$A$ histogram for this data is shown in the figure.

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Similar Questions

Find the mean and the median of the observations: $72, 15, 28, 31, 32, 51, 44, 43$ and $62$.

The following observations are arranged in ascending order:
$26, 29, 42, 53, x, x+2, 70, 75, 82, 93$
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To draw a histogram to represent the following frequency distribution:
Class interval $5-10$ $10-15$ $15-25$ $25-45$ $45-75$
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The adjusted frequency for the class $25-45$ is:

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For drawing a frequency polygon of a continuous frequency distribution,we plot the points whose ordinates are the frequencies of the respective classes and abscissae are respectively:

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