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(D) Number of observations $(n) = 10,$ which is even.Therefore,the median is the mean of the $\left(\frac{n}{2}ight)^{	ext{th}}$ and $\left(\frac{n

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$64$

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(D) Number of observations $(n) = 10,$ which is even.Therefore,the median is the mean of the $\left(\frac{n}{2}ight)^{	ext{th}}$ and $\left(\frac{n}{2}+1ight)^{	ext{th}}$ observations,i.e.,the $5^{	ext{th}}$ and $6^{	ext{th}}$ observations.Here,the $5^{	ext{th}}$ observation $= x$ and the $6^{	ext{th}}$ observation $= x+2$.Median $= \frac{x + (x+2)}{2} = \frac{2x+2}{2} = x+1$.Given that the median is $65,$ we have $x+1 = 65$.Therefore,$x = 65 - 1 = 64$.Thus,the value of $x$ is $64.$

The following observations are arranged in ascending order:
$26, 29, 42, 53, x, x+2, 70, 75, 82, 93$
If the median is $65,$ find the value of $x$.

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The following observations are arranged in ascending order:$26, 29, 42, 53, x, x+2, 70, 75, 82, 93$If the median is $65,$ find the value of $x$.