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(C) The volume of a cylinder is given by $V = \pi r^2 l$,where $r$ is the radius and $l$ is the length.Given: $l = 5.0 \; cm$,$\Delta l = 0.1 \; cm$,$

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$3$

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(C) The volume of a cylinder is given by $V = \pi r^2 l$,where $r$ is the radius and $l$ is the length.Given: $l = 5.0 \; cm$,$\Delta l = 0.1 \; cm$,$d = 2.00 \; cm$,$\Delta d = 0.01 \; cm$.The radius $r = d/2 = 1.00 \; cm$. The error in radius is $\Delta r = \Delta d / 2 = 0.005 \; cm$.The relative error in volume is given by $\frac{\Delta V}{V} = 2 \frac{\Delta r}{r} + \frac{\Delta l}{l}$.Percentage error = $\left( 2 \frac{\Delta r}{r} + \frac{\Delta l}{l} ight) 	imes 100$.Substituting the values: $\left( 2 	imes \frac{0.005}{1.00} + \frac{0.1}{5.0} ight) 	imes 100$.$= (2 	imes 0.5 \% + 2 \%) = 1 \% + 2 \% = 3 \%$.

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