The length (in m) of the bridge,which a train | vedclass

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Question

(C) Let the length of the bridge be $x \; m$.Total distance covered by the train to cross the bridge = (Length of train + Length of bridge) = $(130 +

Vedclass · Accepted Answer

$245$

Vedclass · Answer

(C) Let the length of the bridge be $x \; m$.Total distance covered by the train to cross the bridge = (Length of train + Length of bridge) = $(130 + x) \; m$.Speed of the train = $45 \; km/hr$.Convert speed to $m/s$: $45 	imes \frac{5}{18} = \frac{225}{18} = 12.5 \; m/s$.Time taken = $30 \; s$.Using the formula: $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$.$130 + x = 12.5 	imes 30$.$130 + x = 375$.$x = 375 - 130 = 245 \; m$.Thus,the length of the bridge is $245 \; m$.

The length (in $m$) of the bridge,which a train $130 \; m$ long and travelling at $45 \; km/hr$ can cross in $30 \; s$,is:

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