(A) First,simplify the expression inside the parenthesis: $\frac{i - 1}{i + 1} = \frac{(i - 1)(i - 1)}{(i + 1)(i - 1)} = \frac{i^2 - 2i + 1}{i^2 - 1}

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(A) First,simplify the expression inside the parenthesis: $\frac{i - 1}{i + 1} = \frac{(i - 1)(i - 1)}{(i + 1)(i - 1)} = \frac{i^2 - 2i + 1}{i^2 - 1} = \frac{-1 - 2i + 1}{-1 - 1} = \frac{-2i}{-2} = i$. Thus,the expression becomes $i^n$. For $i^n$ to be a real number,$n$ must be a multiple of $2$ (since $i^2 = -1$ and $i^4 = 1$). The least positive integer $n$ is $2$.