The lattice energies of NaCl,NaF,KCl,and RbCl | vedclass

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Question

(C) Lattice energy is the energy required to completely separate one mole of a solid ionic compound into its gaseous constituent ions. Lattice energy

Vedclass · Accepted Answer

$RbCl < KCl < NaCl < NaF$

Vedclass · Answer

(C) Lattice energy is the energy required to completely separate one mole of a solid ionic compound into its gaseous constituent ions. Lattice energy is inversely proportional to the inter-ionic distance $(r_0 = r_+ + r_-)$. As the size of the ions decreases,the inter-ionic distance decreases,which leads to stronger electrostatic forces of attraction and higher lattice energy. Comparing the given compounds: $RbCl$ ($Rb^+$ is largest),$KCl$ $(K^+)$,$NaCl$ $(Na^+)$,$NaF$ ($F^-$ is smallest). The size order of ions is $Rb^+ > K^+ > Na^+$ and $Cl^- > F^-$. Therefore,the lattice energy order is $RbCl < KCl < NaCl < NaF$.

The lattice energies of $NaCl$,$NaF$,$KCl$,and $RbCl$ follow the order:

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