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(D) According to Bragg's law, the condition for diffraction is $2d \sin 	heta = n\lambda$, where $d$ is the interplanar spacing, $	heta$ is the glan

Vedclass · Accepted Answer

$20$

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(D) According to Bragg's law, the condition for diffraction is $2d \sin 	heta = n\lambda$, where $d$ is the interplanar spacing, $	heta$ is the glancing angle, $n$ is the order of diffraction, and $\lambda$ is the wavelength of $X$-rays.To find the maximum wavelength $\lambda_{\max}$ that can be studied, we set the order of diffraction to $n = 1$ and the maximum value of $\sin 	heta$ to $1$ (since $\sin 	heta \leq 1$).Thus, $\lambda_{\max} = 2d$.Given $d = 10^{-7} 	ext{ cm} = 10^{-7} 	imes 10^7 	ext{ Å} = 10 	ext{ Å}$.Substituting the value of $d$, we get $\lambda_{\max} = 2 	imes 10 	ext{ Å} = 20 	ext{ Å}$.

The largest distance between the interatomic planes of a crystal is $10^{-7} \text{ cm}$. The upper limit for the wavelength of $X$-rays which can be usefully studied with this crystal is ............ $\mathring{A}$.

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