The kinetic energy of an electron is $5.65 \times 10^{-25} \ J$. Find the frequency of the electron.
(N/A) The kinetic energy $(K.E.)$ of an electron is given by the formula $K.E. = h \nu$,where $h$ is Planck's constant $(6.626 \times 10^{-34} \ J \cdot s)$ and $\nu$ is the frequency.
Given $K.E. = 5.65 \times 10^{-25} \ J$.
Therefore,$\nu = \frac{K.E.}{h} = \frac{5.65 \times 10^{-25} \ J}{6.626 \times 10^{-34} \ J \cdot s}$.
$\nu \approx 8.53 \times 10^8 \ Hz$.
Given $K.E. = 5.65 \times 10^{-25} \ J$.
Therefore,$\nu = \frac{K.E.}{h} = \frac{5.65 \times 10^{-25} \ J}{6.626 \times 10^{-34} \ J \cdot s}$.
$\nu \approx 8.53 \times 10^8 \ Hz$.
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