The inverse of the proposition (p wedge sim q | vedclass

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Question

(B) The given proposition is $(p \wedge \sim q) \rightarrow r$. The inverse of a conditional statement $A \rightarrow B$ is defined as $\sim A \righta

Vedclass · Accepted Answer

$(\sim p) \vee q \rightarrow (\sim r)$

Vedclass · Answer

(B) The given proposition is $(p \wedge \sim q) \rightarrow r$. The inverse of a conditional statement $A \rightarrow B$ is defined as $\sim A \rightarrow \sim B$. Here,$A = (p \wedge \sim q)$ and $B = r$. Therefore,the inverse is $\sim (p \wedge \sim q) \rightarrow \sim r$. Using De Morgan's Law,$\sim (p \wedge \sim q) \equiv \sim p \vee \sim (\sim q) \equiv \sim p \vee q$. Thus,the inverse is $(\sim p) \vee q \rightarrow (\sim r)$.

The inverse of the proposition $(p \wedge \sim q) \rightarrow r$ is:

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