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(B) The given matrix is the identity matrix of order $3$,denoted by $I_3 = \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}$.By the d

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$\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}$

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(B) The given matrix is the identity matrix of order $3$,denoted by $I_3 = \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}$.By the definition of the inverse of a matrix,for any square matrix $A$,if $AB = BA = I$,then $B$ is the inverse of $A$,denoted as $A^{-1}$.For the identity matrix $I$,we know that $I 	imes I = I$.Therefore,the inverse of the identity matrix is the identity matrix itself,i.e.,$I^{-1} = I$.Thus,the inverse of $\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}$ is $\begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix}$.

The inverse of the matrix $\begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}$ is

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