The intensity of $X$-rays from a Coolidge tube is plotted against wavelength as shown in the figure. The minimum wavelength found is ${\lambda _c}$ and the wavelength of the ${K_\alpha }$ line is ${\lambda _k}$. As the accelerating voltage is increased:

  • A
    $({\lambda _K} - {\lambda _C})$ increases
  • B
    $({\lambda _K} - {\lambda _C})$ decreases
  • C
    ${\lambda _K}$ increases
  • D
    ${\lambda _K}$ decreases

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$\Delta \lambda$ is the difference between the wavelength of the $K_\alpha$ line and the minimum wavelength of the continuous $X$-ray spectrum when the $X$-ray tube is operated at a voltage $V$. If the operating voltage is changed to $V / 3$,then the above difference is $\Delta \lambda^{\prime}$. Then:

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