The minimum wavelength of the X-rays produced | vedclass

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(D) The energy of an electron accelerated through a potential difference $V$ is given by $E = eV$.When this electron strikes the target,it produces $X

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$1/V$

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(D) The energy of an electron accelerated through a potential difference $V$ is given by $E = eV$.When this electron strikes the target,it produces $X$-rays. The maximum energy of the emitted $X$-ray photon corresponds to the total kinetic energy of the electron,which is $E_{max} = h
u_{max} = \frac{hc}{\lambda_{min}}$.Equating the two,we get $eV = \frac{hc}{\lambda_{min}}$.Rearranging for the minimum wavelength,we find $\lambda_{min} = \frac{hc}{eV}$.Since $h$,$c$,and $e$ are constants,it follows that $\lambda_{min} \propto \frac{1}{V}$.

The minimum wavelength of the $X$-rays produced by electrons accelerated through a potential difference of $V$ volts is directly proportional to

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