The instantaneous values of current and emf i | vedclass

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Question

(A) The instantaneous current is given by $I = I_0 \sin(\omega t + \phi_I)$,where $\phi_I = 0$.The instantaneous emf is given by $E = E_0 \sin(\omega

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$-\pi/6 \, rad$

Vedclass · Answer

(A) The instantaneous current is given by $I = I_0 \sin(\omega t + \phi_I)$,where $\phi_I = 0$.The instantaneous emf is given by $E = E_0 \sin(\omega t + \phi_E)$,where $\phi_E = -\pi/6$.The phase difference between $E$ and $I$ is defined as $\Delta \phi = \phi_E - \phi_I$.Substituting the values,we get $\Delta \phi = (-\pi/6) - (0) = -\pi/6 \, rad$.Therefore,the phase difference is $-\pi/6 \, rad$.

The instantaneous values of current and emf in an $AC$ circuit are $I = 1/\sqrt{2} \sin(314t) \, A$ and $E = \sqrt{2} \sin(314t - \pi/6) \, V$ respectively. The phase difference between $E$ and $I$ will be

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