$AC$ measuring instruments measure

The peak value of an alternating current is $5 \ A$ and its frequency is $60 \ Hz$. Find its $rms$ value and the time taken to reach the peak value of current starting from zero.

$A$ resistance of $20 \Omega$ is connected to an alternating current source of $110 V$. If the frequency of the $A.C.$ source is $50 Hz$,then the time taken by the current to change from its maximum value to the $R.M.S.$ value is

The alternating current is given by $i = \left\{\sqrt{42} \sin \left(\frac{2 \pi}{T} t\right) + 10\right\} \text{ A}$. The $r.m.s.$ value of this current is $\text{A}$.

What is $AC$ voltage? Write the equation for $AC$ voltage.

The $r.m.s.$ value of an $AC$ of $50 \ Hz$ is $10 \ A$. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be: