The increasing order of stability of the foll | vedclass

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Question

(B) The stability of free radicals is determined by resonance and inductive effects.Resonance provides greater stabilization than the inductive effect

Vedclass · Accepted Answer

$(CH_3)_2 \dot{C}H < (CH_3)_3 \dot{C} < (C_6H_5)_2 \dot{C}H < (C_6H_5)_3 \dot{C}$

Vedclass · Answer

(B) The stability of free radicals is determined by resonance and inductive effects.Resonance provides greater stabilization than the inductive effect.$(C_6H_5)_3 \dot{C}$ is the most stable due to resonance with three phenyl rings.$(C_6H_5)_2 \dot{C}H$ is the next most stable due to resonance with two phenyl rings.$(CH_3)_3 \dot{C}$ (tertiary alkyl radical) is more stable than $(CH_3)_2 \dot{C}H$ (secondary alkyl radical) due to the greater inductive effect and hyperconjugation.Thus,the increasing order of stability is: $(CH_3)_2 \dot{C}H < (CH_3)_3 \dot{C} < (C_6H_5)_2 \dot{C}H < (C_6H_5)_3 \dot{C}$.

The increasing order of stability of the following free radicals is:

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