An ovule which becomes curved so that the nuc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a $Hemitropous$ (or $Hemianatropous$) ovule,the body of the ovule becomes curved such that the $nucellus$ and $embryo$ $sac$ lie at a right ang

Vedclass · Accepted Answer

Hemitropous

Vedclass · Answer

(A) In a $Hemitropous$ (or $Hemianatropous$) ovule,the body of the ovule becomes curved such that the $nucellus$ and $embryo$ $sac$ lie at a right angle $(90^{\circ})$ to the $funicle$.Examples include members of the family $Ranunculaceae$.In $Campylotropous$ ovules,the body is curved,but the $micropyle$ is directed towards the $chalaza$,and the $nucellus$ is bent.In $Anatropous$ ovules,the body is inverted $180^{\circ}$,bringing the $micropyle$ close to the $hilum$.In $Orthotropous$ ovules,the $micropyle$,$chalaza$,and $funicle$ lie in a straight line.

An ovule which becomes curved so that the nucellus and embryo sac lie at right angles to the funicle is:

Similar Questions

$A$ circle with center at $(2,4)$ is such that the line $x+y+2=0$ cuts a chord of length $6$. The radius of the circle is

Identify the incorrect statement among the following.

If $x = \frac{1 - t^2}{1 + t^2}$ and $y = \frac{2at}{1 + t^2}$,then $\frac{dy}{dx} = $

If $y$ is a function of $x$ and $\log(x+y) = 2xy$,then the value of $y'(0)$ is

The equation of the line passing through the point $(-1, 3, -2)$ and perpendicular to each of the lines $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ and $\frac{x+2}{-3} = \frac{y-1}{2} = \frac{z+1}{5}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module